要看一種物質是氧化還是還原性，關鍵在于它所含粒子的情況。在氫氧化鉀中，鉀有+ 1價，所以它只能得到一個電子被還原，所以它在氧化。答案中有個缺陷，oh沒有氧化或還原。為什么?因為所謂的電解什么的并不是一個真正的反應過程,例如,硅與氫氧化鈉反應,方程式是氫氧化鈉和氫氧化氧化,但氧化劑是水,反應是誤導,因為這兩個虱子都寫在一起。記住，一般來說，當你得到高的正價時，你只顯示氧化，當你得到低的負價時，你只顯示還原。
　　To see whether a substance is redox or redox, the key lies in the case of the particles it contains. In potassium hydroxide, potassium has a + 1 valence, so it can only get one electron to be reduced, so it is oxidized. One drawback of the answer is that Oh is not oxidized or reduced. Why? Because what is called electrolysis is not a real reaction process, for example, the reaction of silicon with sodium hydroxide. The equation is sodium hydroxide and hydroxide oxidation, but the oxidant is water. The reaction is misleading, because both lice are written together. Remember, generally speaking, when you get the highest positive valence, you only show oxidation, and when you get the lowest negative valence, you only show reduction.
　　臭氧與氫氧化鉀的反應是4KOH+4O3+2H2O=4KO3·H2O+O2
　　The reaction between ozone and potassium hydroxide is 4KOH+4O 3+2H 2=4KO 3.H 2+O 2.
　　的原因是臭氧氧化的反應很強,有一定的還原性和KOH,反應會產生兩個橙紅色固體KO3·H2O一水臭卡莉,稱為“臭卡莉】【,O3是減少O2和O3 -氧氣】【】【臭氧根,和原來的氧化態(tài),二也是O3氧化的氧-(部分)。
　　The reason is that the ozone oxidation reaction is very strong, with certain reductivity and KOH. The reaction produces two orange-red solid KO 3 H 2 2 O 3

　　反應的本質是臭氧的氧化——氧的氧化態(tài),結果O3的形成和氧氣,但電子的總數(shù)在O3 – 23,順,容易分解,在稀溶液將很快分解成氧氣和KOH,如果它是一個稀溶液,反應產物是氧氣,KOH保持不變。在濃縮液中，KO3·H2O析出為橙紅色固體，然后緩慢分解為KO2[過氧化物鉀]和O2
　　The essence of the reaction is the oxidation of ozone – the oxidation state of oxygen, resulting in the formation of O3 and oxygen, but the total number of electrons in O3 – 23, cis, easy to decompose, in dilute solution will soon decompose into oxygen and KOH, if it is a dilute solution, the reaction product is oxygen, KOH remains unchanged. In the concentrated solution, KO_3 H_2 precipitates into orange solid, then slowly decomposes into KO_2 [potassium peroxide] and O_2.
　　結論:臭氧與氫氧化鉀反應生成氧化鉀和氧。如果溶液很薄，產物就是氧。
　　Conclusion: Ozone reacts with potassium hydroxide to produce potassium oxide and oxygen. If the solution is very thin, the product is oxygen.
　　注:該反應也適用于氫氧化銣和氫氧化銫，但不適用于氫氧化鈉，因為臭氧化鈉穩(wěn)定性低，可立即分解為氧和氫氧化鈉。
　　Note: This reaction is also applicable to rubidium hydroxide and cesium hydroxide, but not to sodium hydroxide, because the stability of sodium ozonate is low, it can be immediately decomposed into oxygen and sodium hydroxide.